Løs likningen
Posted: 31/08-2006 08:55
Hvordan løser man denne?
[tex]$${4 \over x} + {2 \over {x - 2}} \equiv {1 \over {x^2 - 2x}}$$[/tex]
[tex]$${4 \over x} + {2 \over {x - 2}} \equiv {1 \over {x^2 - 2x}}$$[/tex]
Fellesnevner er:x[sup]2[/sup]-2x=x(x-2)Hypernicus wrote:Hvordan løser man denne?
[tex]$${4 \over x} + {2 \over {x - 2}} \equiv {1 \over {x^2 - 2x}}$$[/tex]
[tex]\frac{4}{x}+\frac{2}{x-2}=\frac{1}{x(x-2)}\\4(x-2)+2x=1\\6x=9\\x=\frac{3}{2}[/tex]