Hei.
Noen som kan hjelpe med denne grenseverdien?
lim x^3-8
x 2 x^2-4
Takker for alle svar:)
Grenseverdi
Moderators: Aleks855, Gustav, Nebuchadnezzar, Janhaa, DennisChristensen, Emilga
Mener du
[tex]\lim_{x \rightarrow 2}\ \frac{x^3 - 8}{x^2 - 4}[/tex]
[tex]= \lim_{x \rightarrow 2}\ \frac{(x-2)(x^2 + 2x + 4)}{(x+2)(x-2)}[/tex]
[tex]= \lim_{x \rightarrow 2}\ \frac{x^2 + 2x + 4}{x + 2}[/tex]
[tex]= \lim_{x \rightarrow 2}\ \frac{12}{4} = 3[/tex]
[tex]\lim_{x \rightarrow 2}\ \frac{x^3 - 8}{x^2 - 4}[/tex]
[tex]= \lim_{x \rightarrow 2}\ \frac{(x-2)(x^2 + 2x + 4)}{(x+2)(x-2)}[/tex]
[tex]= \lim_{x \rightarrow 2}\ \frac{x^2 + 2x + 4}{x + 2}[/tex]
[tex]= \lim_{x \rightarrow 2}\ \frac{12}{4} = 3[/tex]