Oppgave 1
f(t)=0.02t3+0.6t2+4.1f′(t)=0.06t2+1.2t
g(x)=x2⋅ e2xg′(x)=2x⋅ e2x+x2⋅ 2e2x=2x⋅ e2x(1+x)
h(x)=ln(x3+1)h′(x)=(lnu)′⋅ (x3+1)′ =1x3+1⋅ 3x2 =3x2x3+1