kan noen svare meg på dette?
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				Solar Plexsus
 - Over-Guru

 - Posts: 1686
 - Joined: 03/10-2005 12:09
 
[tex]\frac{3a}{4} \:+\: \frac{1}{4}b(b \:-\: \frac{a}{b}) \:+\: \frac{1}{2}b^2 \;=\; \frac{3a}{4} \:+\: \frac{b^2}{4} \:-\: \frac{a}{4} \:+\: \frac{b^2}{2} \;=\; \frac{a}{2} \:+\: \frac{3b^2}{4}.[/tex]
            
			
									
									
						
