kan noen svare meg på dette?
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[tex]\frac{3a}{4} \:+\: \frac{1}{4}b(b \:-\: \frac{a}{b}) \:+\: \frac{1}{2}b^2 \;=\; \frac{3a}{4} \:+\: \frac{b^2}{4} \:-\: \frac{a}{4} \:+\: \frac{b^2}{2} \;=\; \frac{a}{2} \:+\: \frac{3b^2}{4}.[/tex]