[tex]2(\frac{x}{2} + 1)^2 - (\frac{x}{4} + \frac{3}{2})(2x - 3) = 2(x - 1) - \frac{3x + 2}{4}[/tex]
så kan vi ta ledd for ledd:
[tex]2(\frac{x}{2} + 1)^2 = 2(\frac{x}{2} + 1)(\frac{x}{2} + 1) = 2(\frac{x^2}{4} + \frac{2x}{2} + 1) = \frac{2x^2}{4} + \frac{4x}{2} + 2[/tex]
[tex](\frac{x}{4} + \frac{3}{2})(2x-3) = (\frac{2x^2}{4} - \frac{3x}{4} + \frac{6x}{2} - \frac{9}{2})[/tex]
[tex]2(x-1) = 2x - 2[/tex]
Så då blir ligningen:
[tex]\frac{2x^2}{4}+\frac{4x}{2} + 2 - \frac{2x^2}{4} + \frac{3x}{4} - \frac{6x}{2} + \frac{9}{2} = 2x - 2 - \frac{3x+2}{4}[/tex]
[tex]\frac{4x}{2} + 2 + \frac{3x}{4} - \frac{6x}{2} + \frac{9}{2} = 2x - 2 - \frac{3x+2}{4}[/tex]
[tex]\frac{8x}{4} + \frac{8}{4} + \frac{3x}{4} - \frac{12x}{4} + \frac{18}{4} = \frac{8x}{4} - \frac{8}{4} - \frac{3x+2}{4}[/tex]
[tex]8x + 3x - 12x - 8x + 3x = -8 - 2 - 8 - 18[/tex]
[tex]-6x = -36[/tex]
[tex]x = 6[/tex]
Det var gøy
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